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3 years ago

14

Pls help

1 answer:

solong [7]3 years ago

7 0

Ok let’s solve it

5(x-2)^2-20=0

first let’s foil (x-2)

5(x^2-4x+4) -20=0

now distribute the 5

5x^2 -20x +20 -20 = 0

combine like terms

5x^2-20x=0

take the gcf

5x(x-4)=0

x=0, 4

solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k

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