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GaryK [48]
3 years ago
8

Add. −6+(−5) 11 −1 −11 I don't know.

Mathematics
2 answers:
Wittaler [7]3 years ago
7 0

Answer:

11

Step-by-step explanation:

-6-5

+11

Hope it is helpful

Scrat [10]3 years ago
6 0

Answer:

- 11

Step-by-step explanation:

- 6 + ( - 5) \\  =  - 6 - 5  \\ =  - 11

<h3>Hope it is helpful....</h3>
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Find the measures of the angles of a right triangle where one of the two acute angles measures 5 times the other
Alina [70]

Answer:

Since it is a right angle, you know that the angle measures 90 degrees. Since one acute angle measures 5x (times) the other, you would set it up in equation format as 5x + x = 90.


5x + x = 6x, so

6x = 90

you divide both both sides by 6 (90/6) = 15


To find the measure of the angle that is 5x (times) the other, you do 5(15) = 75 degrees and the other angle is 15 degrees, which adds up to 90 degrees.



Mark me brainiest


5 0
4 years ago
X-3 (2x-7)=76<br> what is x
liq [111]
     x - 3(2x - 7) = 76
x - 3(2x) - 3(-7) = 76
       x - 6x + 21 = 76
            -5x + 21 = 76
            <u>       - 21  - 21</u>
                    <u>-5x</u> = <u>55</u>
                     -5     -5
                       x = -11
<u />
5 0
3 years ago
Find the discounted price of the teddy bear which has a regular price of $450.
GuDViN [60]
You will pay $360 for a item with original price of $450 when discounted 20%. 450x0.2=90.00 then 450-90=360
6 0
3 years ago
A 2.0 kg cart moving right at 5.0 on a frictionless track collides with a 3.0 kg cart initially at rest. The 2.0 kg
Wewaii [24]

final speed of the 3.0 kg cart is 2.67 m/s .

<u>Step-by-step explanation:</u>

Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg  cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)

⇒ m_1(v_1)+m_2(v_2) =m_1(v_3)+m_2(v_4)

⇒ 2(5)+3(0) =2(1)+3(v_4)

⇒ 10 =2+3(v_4)

⇒ 3(v_4) = 8

⇒ (v_4) = \frac{8}{3}

⇒ (v_4) = 2.67

Therefore, final speed of the 3.0 kg cart is 2.67 m/s .

4 0
4 years ago
Two ways to do a number line
lana66690 [7]
You can use a number line to add and subtract 
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3 years ago
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