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3 years ago

In how many different ways can 4 students be seated with in a row?

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

<span>4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.</span>

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(3•x)•3-2=1 <br><br> I missed a lot of school and don’t know how to solve for x could you help me

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$(3x) \times 3 - 2 = 1$

$(3x \times 3) - 2 = 1$

$9x - 2 = 1$

Add sides 2

$9x - 2 + 2 = 1 + 2$

Simplification

$9x = 3$

Divide sides by 9

$\frac{9x}{9} = \frac{3}{9} \\$

$\frac{9}{9} x = \frac{3}{9} \\$

$x = \frac{3}{3 \times 3} \\$

$x = \frac{1}{3} \\$

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3 years ago

A company designs its packing so that it is a cylinder with a diameter of 4 inches and a height of 7 inches

jenyasd209 [6]

Answer:

Step-by-step explanation:due to the lack of information I'm gonna have to include that the total amount of space would be 28

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2 years ago

What will be the value of the 22nd coefficient of a binomial raised to the power 25

Alona [7]

Step-by-step answer:

We are looking at the coefficient of the 22nd term of (x+y)^25.

Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.

The twenty-second term of (x+y)^25 is given by the binomial theorem as

( 25!/(21!4!) ) x^21*y^4

=25*24*23*22/4! x^21y^4

= 12650 x^21 y^4

The coefficient required is therefore 12650, for a binomial with unit valued coefficients.

For other binomials, substitute the values for x and y and expand accordingly.

Question would have been more clearly stated if the actual binomial was given, as commented above.

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3 years ago

A pastry shop earned $9,026 over the course of 5 days. How much did they earn on just 1 day? Note: do not write a dollar sign

o-na [289]

Answer:

9207

Step-by-step explanation:

because if you multiply

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3 years ago

Sixteen is the same as one and two-tenths times a number added to negative 8

Archy [21]

Answer:

Step-by-step explanation:

16=1 2/10R + -8

16+8= 12/10R

24=12/10R

R=20

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3 years ago

Read 2 more answers