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77julia77 [94]
3 years ago
8

In how many different ways can 4 students be seated with in a row?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
<span>4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.</span>
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Step-by-step explanation:

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In spring 2014, faculty from the City University of New York (CUNY) reported on a randomized controlled trial they conducted. Th
Lady_Fox [76]

Answer:

A) explanatory variable is "The extra support given by faculties"

B) the response variable is;

"How successful students who were placed directly into college - level statistics were able to outperform both elementary algebra treatment groups."

C) Confounding Variable is "ability of students to be successful or pass"

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Step-by-step explanation:

A) An explanatory variable is simply a type of independent variable used to explain the changes that occur in another variable. Furthermore, it can be manipulated by the researcher and is also used to predict differences in the response variable.

Now, from the question, we see that the variable "extra support by the faculties" is used to determine how successful community college students who were placed directly into college - level statistics were in outperforming both elementary algebra treatment groups.

Thus, the explanatory variable is "The extra support given by faculties"

B) In answer A above, we saw that the explanatory variable is used to predict the response variable.

We saw that the explanatory variable predicted how successful community college students who were placed directly into college - level statistics were in outperforming both elementary algebra treatment groups.

Thus, the response variable is;

"How successful students who were placed directly into college - level statistics were able to outperform both elementary algebra treatment groups."

C) A confounding variable is one that influences or changes the effect of the dependent & independent variable. It is therefore used to influence the result/outcome of an experiment/research.

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Answer:

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P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}

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Answer:

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