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3 years ago

Can y’all plz help me

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

Answer:

D. 10

Step-by-step explanation:

Assuming that <COA is a right angle, we can say that the two given angles are complementary

complementary angles are angles that add up to 90 degrees

this means we can create this equation: 3x + 46 + 14 = 90

so subtract 46 and 14 from 90: 3x = 30

divide both sides by 3: x = 10

pishuonlain [190]3 years ago

3 0

Answer:

I think that it is letter D

Step-by-step explanation:

sorry if im wrong. but i hope this helps! :)

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Your answer to what mean is 395

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3 years ago

Read 2 more answers

What represents the period of the sine function represented in the graph?

Kisachek [45]

Answer:

D. pi

Step-by-step explanation:

7 0

3 years ago

Please help I don’t really understand how to go about it.

Airida [17]

$\bf \textit{sum of an arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
S_n=795\\
a_1=102\\
a_n=57
\end{cases}
\\\\\\
795=\cfrac{n(102+57)}{2}\implies 1590=159n
\\\\\\
\cfrac{1590}{159}=n\implies 10=n\\\\
-------------------------------$

so the nth term is really the 10th term, and we know that's 57, thus

$\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=10\\
a_{10}=57\\
a_1=102
\end{cases}
\\\\\\
57=102+(10-1)d\implies 57=102+9d\implies -45=9d
\\\\\\
\cfrac{-45}{9}=d\implies -5=d$

so, that's the common difference... .so you'd surely know what the 3rd term is, notice the first one is 102.

3 0

3 years ago

20) Use the distributive property to factor the expression. 10xz − 20yz A) z(10x − 20y) B) 10(xz − 2yz) C) 10z(x − 2y) D) xyz(10

melisa1 [442]

Answer:

C. 10z(x - 2y)

Step-by-step explanation:

10xz − 20y

Factor the terms

Factors of 10xz = 2 × 5 × x × z

Factors of -20yz = (-1) × 2 × 2 × 5 × y × z

Identify their greatest common factor

The common factors are 2, 5, and z. The greatest common factor is 10z.

Rewrite them with the GCF as a factor

10xz = 10z × x

-20yz = 10z × (-2y)

Replace the terms in the original expression with the factored terms

10xz − 20yz = 10z(x) + 10z(-2y)

Use the distributive property to isolate the greatest common factor

10z(x) + 10z(-2y) = 10z(x - 2y)

4 0

3 years ago

Independent random samples from two regions in the same area gave the following chemical measurements (ppm). Assume the populati

Basile [38]

Answer:

d. The interval contains only negative numbers. We cannot say at the required confidence level that one region is more interesting than the other.

Step-by-step explanation:

Hello!

You have the data of the chemical measurements in two independent regions. The chemical concentration in both regions has a Gaussian distribution.

Be X₁: Chemical measurement in region 1 (ppm)

Sample 1

n= 12

981 726 686 496 657 627 815 504 950 605 570 520

μ₁= 678

σ₁= 164

Sample mean X[bar]₁= 678.08

X₂: Chemical measurement in region 2 (ppm)

Sample 2

n₂= 16

1024 830 526 502 539 373 888 685 868 1093 1132 792 1081 722 1092 844

μ₂= 812

σ₂= 239

Sample mean X[bar]₂= 811.94

Using the information of both samples you have to determina a 90% CI for μ₁ - μ₂.

Since both populations are normal and the population variances are known, you can use a pooled standard normal to estimate the difference between the two population means.

[(X[bar]₁-X[bar]₂)± $Z_{1-\alpha /2}$ * $\sqrt{\frac{Sigma^2_1}{n1}+\frac{Sigma^2_2}{n_2} }$ ]

$Z_{1-\alpha /2}= Z_{0.95}= 1.648$

[(678.08-811.94)±1.648* $\sqrt{\frac{164^2}{12}+\frac{239^2}{16} }$ ]

[-259.49;-8.23]ppm

Both bonds of the interval are negative, this means that with a 90% confidence level the difference between the population means of the chemical measurements of region 1 and region 2 may be included in the calculated interval.

You cannot be sure without doing a hypothesis test but it may seem that the chemical measurements in region 1 are lower than the chemical measurements in region 2.

I hope it helps!

6 0

4 years ago