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Masja [62]
4 years ago
11

Solve the system of equations.

Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
7 0
There are two possible answers:
(6, -12)
(8, 14)
You might be interested in
A triangle has vertices at B(−3, 0), C(2, −1), D(−1, 2). Which series of transformations would produce an image with vertices B″
vichka [17]

We must apply the <em>transformation</em> rules (x, y) → (- x, y) and (x, y) → (x + 1, y + 1) to generate the vertices B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3). (Right choice: B)

<h3>How to determine the right transformation rules for a set of three points</h3>

In this question we have three points on a <em>Cartesian</em> plane: B(x, y) = (- 3, 0), C(x, y) = (2, - 1), D(x, y) = (- 1, 2). First, we proceed to apply the <em>transformation</em> rule (x, y) → (- x, y):

B'(x, y) = (3, 0), C'(x, y) = (- 2, -1), D'(x, y) = (1, 2)

Then, we use the <em>transformation</em> rule (x, y) → (x + 1, y + 1):

B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3)

Then, we must apply the <em>transformation</em> rules (x, y) → (- x, y) and (x, y) → (x + 1, y + 1) to generate the vertices B''(x, y) = (4, 1), C''(x, y) = (- 1, 0), D''(x, y) = (2, 3).

To learn more on transformation rules: brainly.com/question/9201867

#SPJ1

7 0
2 years ago
Consider two populations of coins, one of pennies and one of quarters. A random sample of 25 pennies was selected, and the mean
Alexus [3.1K]

Answer:

No, the conditions for normality have not been met because the sample size for the quarters is not large enough and no information is given about the distributions of the populations.

Step-by-step explanation:

"The Kolmogorov-Smirnov test (K-S) and Shapiro-Wilk (S-W) test are designed to test normality by comparing your data to a normal distribution with the same mean and standard deviation of your sample. If the test is NOT significant, then the data are normal, so any value above .05 indicates normality"

5 0
3 years ago
Read 2 more answers
What is the area, in square millimeters, of a right triangle with a hypotenuse of 68 millimeters and a leg of 60 millimeters?
Paladinen [302]
First, we have to solve the sides of the right triangle by using the Pythagorean theorem: a² + b² = c² where c is the length of the hypotenuse. Then, we can use the legs as length and height of the triangle and find the area by 1/2(base x height).

x² + 60² = 68²
x² + 3600 = 4624
x² = 1024
x = √1024
x = 32 = length of the other side

A = (1/2)(32) (60) = 960 mm²
6 0
3 years ago
Write thThe bookstore is selling a series of 4 books for $97.50. What is the unit price for one book? Round your answer to the n
Sveta_85 [38]

Answer: $24.47

Step-by-step explanation: I don’t understand the kilometers.

8 0
3 years ago
In 1999. Sara and her brother Xzavier got money when their rich uncle died. They
Hunter-Best [27]

Answer:

$406,300

Step-by-step explanation:

$2,700 + $3,600 = $6,300

$400,000 + $6,300 = $406,300

3 0
3 years ago
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