The ratio of the area of the black circle to the area of the white square to the area of the gray square is π : 4 : 2
<h3>How to determine the ratio of the areas?</h3>
The side length AB is given as:
AB = 8x
The area of the white square is calculated as
White = (AB)²
This gives
White = (8x)²
Evaluate
White = 64x²
The side length AB represents the diameter of the black circle.
So, the radius is:
r =AB/2
This gives
r = 8x/2 = 4x
The area is then calculated as:
Circle = πr²
This gives
Circle = π(4x)²
Evaluate
Circle = 16πx²
Next, calculate AW and AZ using:
AZ = AW = AB/2
Evaluate
AZ = AW = 8x/2 = 4x
Calculate WZ using the following Pythagoras theorem
WZ² = AW² + AZ²
This gives
WZ² = (4x)² + (4x)²
Evaluate
WZ² = 2(4x)²
Take the square root of both sides
WZ = 4x√2
The area of the gray square is:
Gray = WZ²
This gives
Gray = 2(4x)²
Evaluate
Gray = 32x²
At this point, the areas are:
- White = 64x²
- Circle = 16πx²
- Gray = 32x²
The ratio is then represented as:
Ratio = Circle : White : Gray
This gives
Ratio = 16πx² : 64x² : 32x²
Divide through by 16x²
Ratio = π : 4 : 2
Hence, the ratio of the area of the black circle to the area of the white square to the area of the gray square is π : 4 : 2
Read more about areas at:
brainly.com/question/24487155
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