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3 years ago

30 POINTS FOR ANSWER!! 2 numbers sum 120 and product 400 INSTANT ANSWER NEEDED

1 answer:

4 0

I think the problem is
2X+20=400
You just have to answer I think X and X equals that two numbers I’m not 100% sure but I’m trying to help

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6. A prism has bases that are equilateral triangles with sides lengths of 10 inches and a length of 30 inches.

eimsori [14]

Answer:

The volume of the prism is $1,299\ in^{3}$

Step-by-step explanation:

we know that

The volume of the prism is equal to

$V=BL$

where

B is the area of the triangular base

L is the length of the prism

we have

$L=30\ in$

The area of a equilateral triangle is equal to

$B=\frac{1}{2}(10)^{2} sin(60\°)$

$B=25\sqrt{3}\ in^{2}$

substitute

$V=(25\sqrt{3})(30)=1,299\ in^{3}$

8 0

2 years ago

5÷118.5 Show Ur Work plzz

Molodets [167]

Answer: 0.04219409282

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length

nataly862011 [7]

We have been given that Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length. Wally is 68 inches tall, casts a shadow that is 41 inches in length.

We will use proportions to solve for the height of the statue because proportions state that ratio between two proportional quantities is same.

$\frac{\text{Height of statue}}{\text{Shadow of statue}}=\frac{\text{Height of Wally}}{\text{Shadow of Wally}}$

Upon substituting our given values in above equation, we will get:

$\frac{\text{Height of statue}}{\text{164 cm}}=\frac{\text{68 inch}}{\text{41 inch}}$

$\frac{\text{Height of statue}}{\text{164 cm}}\times \text{164 cm}=\frac{\text{68 inch}}{\text{41 inch}}\times \text{164 cm}$

$\text{Height of statue}=\frac{\text{68 inch}}{1}\times 4$

$\text{Height of statue}=272\text{ inches}$

Therefore, the height of the statue is 272 inches.

5 0

2 years ago

Graph the line 2x + y = 7.

OLga [1]

Answer:f

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places

natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

$\rm 5 \sin \theta = 4\\\\\theta = 0.927 , 2.214$

Then by the integration, we have

$\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\$

$\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\$

On solving, we have

$\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75$

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0

2 years ago