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Marysya12 [62]
3 years ago
8

At 3:30 p.m., you have 15 megabytes of a movie. At 3:45 p.m., you have 75 megabytes. What is the download rate in megabytes per

minute?
Mathematics
1 answer:
snow_lady [41]3 years ago
7 0
Because the time moved up by 15 minutes, we would already know that it would be (blank) megabytes per 15 minutes

75 megabytes - 15 megabytes = 60

this would mean 60 megabytes are downloaded per 15 minutes

simplified by 15, our answer would be 4 megabytes downloaded per minute

both of the answers above would be acceptable :)
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Write the slope-intercept form of the line between the two points.
DENIUS [597]
Answer: Y= -5x+2
First we need to find slope
M= y2-y1/x2-x1
M= -3-2/1-0
M= -5/1
M= -5
Now using slope intercept form we can solve this equation
Y-y1=m(x-x1)
Y-2=-5(x-0)
Y-2=-5x+0
Y= -5x+2
hope this helps!!
Please tell me if I am incorrect, I enjoy learning from my mistakes:)
5 0
2 years ago
In a recent survey of college professors, it was found that the average amount of money spent on entertainment each week was nor
Alenkinab [10]

Answer:

0.0918

Step-by-step explanation:

We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The mean and standard deviation of average spending of sample size 25 are

μxbar=μ=95.25

σxbar=σ/√n=27.32/√25=27.32/5=5.464.

So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The z-score associated with average spending $102.5

Z=[Xbar-μxbar]/σxbar

Z=[102.5-95.25]/5.464

Z=7.25/5.464

Z=1.3269=1.33

We have to find P(Xbar>102.5).

P(Xbar>102.5)=P(Z>1.33)

P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)

P(Xbar>102.5)=0.5-0.4082

P(Xbar>102.5)=0.0918.

Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.

5 0
3 years ago
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
Find the 58th term of the following arithmetic sequence.<br> 13, 19, 25, 31,
pashok25 [27]

Answer:

the answer to this is 355.

source:da brain

6 0
2 years ago
Evaluate the expression for the given value of the variable.
Fudgin [204]

Answer:

The answer is three please give brainliest:D

Step-by-step explanation:

4 0
2 years ago
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