Answer:
The values of 
and 
for a linear system with infinitely many solutions are -2 and 5, respectively.
Step-by-step explanation:
Let 
, if this linear system has infinitely many solutions, then the following conditions must be met:
and 
.
and
The values of and for a linear system with infinitely many solutions are -2 and 5, respectively.
Step-by-step explanation:
Formula:- 4/3*Pi*r^3
= 4/3*22/7*(1/2)^3
Please mark me as brainliest
(sorry if it's too late and you've already figured it out, but here you go anyway)
The easiest way to do this is to start by FOILing then add.
So just start with (x-1)(x-1)
(x-1)(x-1)
Front: (x*x) = x^2
Outer: (x*-1) = -x
inner: (-1*x) = -x
Last: (-1*-1) = 1
Added: x^2 -2x +1
Now take that answer and do the same thing with (x-1). It's basically the same thing, just with an added thing you need to multiply.
(x-1)(x^2-2x+1)
(x*x^2) = x^3
(x*2x) = 2x^2
(x*1) = x
(-1*x^2) = -x^2
(-1*-2x) = 2x
(-1*1) = -1
Now add everything together:
x^3+2x^2+x-x^2+2x-1
The answer is:
x^3+x^2+3x-1
Answer:
13
Step-by-step explanation:
Given parameters:
Number of oranges processed by grower = 2330 oranges
Number of oranges per crate = 96
Unknown:
Number unpacked oranges
Solution:
To solve this problem, divide the total number of oranges by the number of oranges per crate;
Number of unpacked oranges = 
Number of unpacked oranges = 24 
The remaining unpacked is 13.
