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bagirrra123 [75]
3 years ago
14

a basketball coach plotted data about her shooting guards playing time and point scoring in a scatterplot

Mathematics
2 answers:
Nitella [24]3 years ago
5 0

The correct answer is y= 15/22x +6/11. I know this is late but it can be useful to others. :)

bekas [8.4K]3 years ago
4 0

Answer:

The equation of line of best fit is:

y=\dfrac{15}{22}x+\dfrac{6}{11}

Step-by-step explanation:

Clearly from the scatter plot we could observe that the line of the best fit passes through the point (8,6) and (30,21)

We know that the equation of a line, passing through two points (a,b) and (c,d) is calculated by:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here we have:

(a,b)=(8,6) and (c,d)=(30,21)

Hence, the equation of line of best fit is calculated as:

y-6=\dfrac{21-6}{30-8}\times (x-8)\\\\\\y-6=\dfrac{15}{22}\times (x-8)\\\\y-6=\dfrac{15}{22}x-\dfrac{8\times 15}{22}\\\\y=\dfrac{15}{22}x-\dfrac{60}{11}+6\\\\y=\dfrac{15}{22}x+\dfrac{6}{11}

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Evaluate<br>0.035x1.02<br>leaving the answer in standard form​
topjm [15]

Step-by-step explanation:

35 × 10^-3 × 102 × 10 ^-2

35×102 ×10^-3-2

3570× 10^-5

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A private ship carries two types of cargo: large crates and extra-large crates. Each type of crate weighs a specific amount.
Arisa [49]

Answer:

G. 32

Step-by-step explanation:

32 x 335 = 10720

16,100 - 10720 = 5380/190 = 28.3157894737

275 x 32 = 8800

18,800 - 8800 = 10,000/400 = 25 (This is the closer).

30 x 335 = 10,050

16,100 - 10,050 = 6050/190  = 31.8421052632

30 x 275 = 8250

18,800 - 8250 = 10550/400 = 26.375 (Same reason why it does't work)

25 x 335 = 8375

16,100 - 8375 = 7725/190 = 40.6578947368

25 x 275 = 6875

18,800 - 6875 = 11925/400 = 29.8125

24 x 335 = 8040

16,100 - 8040 = 8060/190 = 42.4210526316

24 x 275 = 6600

18,800 - 6600 = 12200/400 = 30.5

8 0
2 years ago
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

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