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Rama09 [41]
3 years ago
7

Solve. x + 9 = –15 x = [1] help please

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0
X + 9 = -15
[1] + 9 = -15
1 + 9 = -15
10 = -15

Answer: 10 does not equal -15
max2010maxim [7]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

x + 9 = -15x = [1]

x - x + 9 = -15x -x = 1

9 - 1 = -16x

8 = 16x

8/16 = 16/16x

1/2 = x

Hope this helps

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Mr.rivas bought a can of paint.he used 3/8 of it to paint a bookshelf.he used 1/4 of it to paint a wagon.he used some of it to p
9966 [12]
The answer is 1/4

because you can add the 3/8 and 1/4, which it will be 5/8.
Then add 5/8 and 1/8 then it eqaul to 6/8
then subtract 1 by 6/8
then you got 2/8 or 1/4
3 0
3 years ago
What is 5 1/8 divided 7/8
garik1379 [7]

0.0915178...........

8 0
3 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
Who can answer this??
Juliette [100K]
The answer is B.

Since it’s a negative x, the line should go down from left to right and cross the origin.
7 0
3 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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