The question ask to find the rate of change of the distance from the paticle to the origin at this instant where as a particle is moving along the curve y = 5sqrt(5x+4) and base on my calculation, I came up with an answer of 254/sqrt(226). I hope you are satisfied with my answer and feel free to ask for more
Answer: 64.60
Step-by-step explanation:
lets do 6.80x9
= 61.20
for the half an hour, divide 6.80 by 2
it would be 3.40
61.20+3.40= 64.60
Answer:8(1/2x - 1/4)> 12 - 2x
a.x > 7
b.x > 7/3
c.x > 5/3
d.x > 5/3
Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x
Hi,
Let's simplify this equation step-by-step.
7−2(5−2x)−10x+25−4x−3
Distribute:
=7+(−2)(5)+(−2)(−2x)+−10x+25+−4x+−3
=7+−10+4x+−10x+25+−4x+−3
Combine Like Terms:
=7+−10+4x+−10x+25+−4x+−3
=(4x+−10x+−4x)+(7+−10+25+−3)
=−10x+19
Answer:
=−10x+19
Have a great day!
