How do I write 7^2 (4 - 15x) in written form?

Mathematics

1 answer:

vesna_86 [32]3 years ago

4 0

Answer:

square of 7 times 4-15x

hope it helps

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Answer:

x= 1, 4

Step-by-step explanation:

$log_{x+2} (9x) =2\\\\9x = (x+2)^2 \\\\(x+2)^2 - 9x = 0\\\\x^2 +4x + 4-9x = 0\\\\x^2 - 5x +4= 0\\\\x^2 - 4x-x+4=0\\\\x(x-4)-1(x-4)=0\\\\(x-4)(x-1)=0\\\\x-4 =0\: or\: x - 1=0\\\\x = 4\: or\: x = 1\\\\x = 1,\: 4$

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Step-by-step explanation:

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Ksivusya [100]

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$(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})$

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Step-by-step explanation:

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