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oksian1 [2.3K]
3 years ago
11

Light bulbs manufactured at a certain factory have a 3% probability of being defective. What is the probability that 5 out of a

shipment of 30 will be defective?
Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0
There is a 3% chance of each light bulb being defective, and we only want 5 of them to be defective. The chance is then:

3\%^5*97\%^{25}

Or this really small number: 1.13474853e-8
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dsp73
Divide amount of grapes by number of people.

= 1/2 lb ÷ 4 people

to divide a fraction, multiply by the reciprocal (inverse)

= 1/2 * 1/4
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Hope this helps! :)
3 0
3 years ago
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Maksim231197 [3]

Given:

The statement is "two sevenths times four sixths".

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The value of the product.

Solution:

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It can be rewritten as:

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3 years ago
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Answer:

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Answer:

Step-by-step explanation:

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now factor r out

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divide by r on both sides

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subtract (3t^4)

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now divide by -5 to isolate the variable (z)

\frac{(n/r)-3t^4}{-5} = z

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Answer:

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