Hi everyone the first person to answer this right gets 40 points

A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is

Yuri [45]

Answer:

x= 44 ounces y = 66 ounces

Step-by-step explanation:

Distribution would be an increase to find 80% salt.

Where we use 4/5 = 80 but use here 4/5.

We find 19/20 but just say 95 for solution B =

Let x = the number of ounces of Solution A

Let y = the number of ounces of Solution B

x + y = 110 y = 110 - x

(70x + 95y) = 4/5 x 110

70x + 95y = 88

70x + 95 y = 88

70x + 95 (88 - x) = 8800 make units equal or for start convert decimalization = same units as 2nd multiplied value.

70x + 8360 - 88x = 8800

-10x - 8360 - 8800 = y

-10x = 440

x = 44 ounces

y = 110- 44

y = 66 ounces

4 0

2 years ago

Read 2 more answers

Which option below is not a potential risk of purchasing a used car?

vlada-n [284]

Answer:

used cars can have a lower initial cost

Step-by-step explanation:

it is not a risk/hinder to purchasing a used car

8 0

2 years ago

15.000 at 9 percent interest

Ksivusya [100]

Answer:

$16.35

Step-by-step explanation:

15 x 1.09 = 16.35

7 0

2 years ago

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

$P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)$

Calculation the value from standard normal z table, we have,

$P(x < 5) =0.7287= 72.87\%$

b) P( port handles 3 or more million tons of cargo per week)

$P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)$

Calculating the value from the standard normal table we have,

$1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%$

c)P( port handles between 3 million and 4 million tons of cargo per week)

$P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%$

$P(3 \leq x \leq 4) = 23.7\%$

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85$

$= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85$

$=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15$

Calculation the value from standard normal z table, we have,

$P( z \leq -1.036) = 0.15$

$\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65$

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0

2 years ago

Jackson played a video game for 1/6 for hour. Hailey played a video game for 1/3 hour. Who played the video game for a greater a

viva [34]

Answer:

hailey played the game longer (1/3 hour).

Step-by-step explanation:

You are deciding which is greater: 1/6 or 1/3.in this case, a smaller denominator (such as 3) produces a greater value.1/3 has a smaller denom. than does 1/6, so 1/3 is greater than 1/6.hailey played the game longer (1/3 hour).

5 0

2 years ago