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Shkiper50 [21]
3 years ago
6

Hi everyone the first person to answer this right gets 40 points

Mathematics
1 answer:
Len [333]3 years ago
6 0
Balance after 4 years is $1440
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Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
Lady bird [3.3K]

Answer:

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m

here m= 1000 kg, g= 9.81 m/s^2  and H= 607 feet = 607×0.305= 185.135 m

hence the potential energy p= 1000×9.81×185.135= 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ

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4 years ago
Convert 6 feet to miles ( round five decimal places
Neporo4naja [7]

Answer:

0.00114

Step-by-step explanation:

Divide length value by 5280

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3 years ago
The price of 3 books is Rs.330 . How many such books can be bought for Rs.550 ?
AysviL [449]
330/3= 110
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Answer is 5 books
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