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DanielleElmas [232]
3 years ago
11

Plsss helpppp I’m stuck

Mathematics
2 answers:
vovangra [49]3 years ago
8 0
C=15
...................
vaieri [72.5K]3 years ago
6 0

Answer:

b = 2c:  Ben's age is twice Cindy's.  So Cindy is 15 years old

(a + b + c) / 3 = 28: Their average age is 28  This tells us nothing as we already have Anne, Ben and Cindy's ages.  It does however give us a quick way to check the answers:

\frac{a + b + c}{3} = 28\\\frac{39 + 30 + 15}{3} = 28\\\frac{84}{3} = 28

Correct, so we know values found are correct.

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Which expressions are equivalent to 3x+3(x+y)3x+3(x+y)3, x, plus, 3, left parenthesis, x, plus, y, right parenthesis ? Choose al
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Answer: Choise A and Choise B.

Step-by-step explanation:

Given the following expression:

3x+3(x+y)

You can simplify it in order to find equivalent expressions.

Appying the Distributive Property, you get:

3x+(3)(x)+(y)(3)=3x+3x+3y

So:

1. If you add the like terms, you get this equivalent expression:

3x+3x+3y=6x+3y

2. But if you factor out 3, you get the following equivalent expression:

3x+3x+3y=3(x+x+y)

Therefore, the expression shown in Choice A and Choise B are equivalents to the expression 3x+3(x+y)

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susie reads 4 pages in 5 minutes at this rate how many pages will she have read in 35 minutes set up a Proportion and solve
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A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

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