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3 years ago

Plsss helpppp I’m stuck

Mathematics

2 answers:

vovangra [49]3 years ago

8 0

C=15
...................

vaieri [72.5K]3 years ago

6 0

Answer:

b = 2c: Ben's age is twice Cindy's. So Cindy is 15 years old

(a + b + c) / 3 = 28: Their average age is 28 This tells us nothing as we already have Anne, Ben and Cindy's ages. It does however give us a quick way to check the answers:

$\frac{a + b + c}{3} = 28\\\frac{39 + 30 + 15}{3} = 28\\\frac{84}{3} = 28$

Correct, so we know values found are correct.

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Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c

slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 16.000

Sample mean, $\bar{x}$ = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338$

Thus, the value of test statistic is 1.338

4 0

4 years ago

What is the unit rate of 183 miles in three hours

Ber [7]

61 miles per hour, because if you divide 183/3 you will get 61.

3 0

3 years ago

Read 2 more answers

What is an average rate of change for this exponential function for the interval from x=0 to x=2?

Drupady [299]

Answer:

Step-by-step explanation:

5 0

3 years ago

∫c x sin y ds, C is the line segment from (0, 1) to (3, 5)

Mnenie [13.5K]

Parameterize the line segment $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=(1-t)\langle0,1\rangle+t\langle3,5\rangle=\langle3t,1+4t\rangle$

where $t\in[0,1]$ . Then

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt$
$\mathrm ds=\|\langle3,4\rangle\|\,\mathrm dt$
$\mathrm ds=5\,\mathrm dt$

So the integral is

$\displaystyle\int_Cx\sin y\,\mathrm ds=5\int_0^1x(t)\sin y(t)\,\mathrm dt$
$=\displaystyle5\int_0^13t\sin(1+4t)\,\mathrm dt$
$=\dfrac{15}{16}(\sin5-\sin-4\cos5)\approx-2.7516$