Ask question

Ask question

All categories

4 years ago

8

Is 0.07 x 10 equivalent 0.07

2 answers:

Nezavi [6.7K]4 years ago

6 0

Answer:

It is the equivalent dose at 10 mm below a specified point of the body. H p (0.07) is the shallow dose equivalent, also referred to as skin dose equivalent or surface dose equivalent. It is the equivalent dose at 0.07 mm below the surface of the body. Currently, RadTarge II measures Hp (10).

Step-by-step explanation:

IrinaVladis [17]4 years ago

5 0

Answer:

No it is .7

Step-by-step explanation:

When you multiply a decimal by 10, then the decimal point shifts over to the left 1 place. So for example, .1 x 10 would equal 1 so .07 x 10 would be .7

You might be interested in

Segment AB is dilated from the origin to create segment A prime B prime at A' (0, 6) and B' (6, 9). What scale factor was segmen

Llana [10]

2 is the answer of the question

7 0

3 years ago

What is the slope of a line that is perpendicular to the line y = x + 5? –2 -1/2 1/2 2

Sliva [168]

y = x + 5

If it's perpendicular the slope is the opposite inverse of the other line,

The slope of line y = x + 5 is 1, because it's the number before x, so, the opposite inverse would be -1/1 = -1.

7 0

3 years ago

A company established in the year 2013. The net profit of the company in the year

Vera_Pavlovna [14]

Answer:

edi wow

Step-by-step explanation:

bwiset ka hahaha

4 0

3 years ago

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago

alexgriva [62]

Answer:

It's - 17x trust me it's right

7 0

3 years ago