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Lapatulllka [165]
3 years ago
14

Kelly rides the bus to work d days each month. She pays a fare of $2.25 each time. On t of those days, she pays an additional fa

re of $0.75 to transfer onto another bus. The expression shown can be used to find her total cost for bus fare for the month.
d × 2.25 + t × 0.75
Which statement explains how to find Kelly’s total bus fare for the month?
Mathematics
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer: A: find the product of D and $2.25 and the product of t and $0.75. Then find the sum of the two products.

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Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be {\sf T_n} is given by ;

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Now , by using the above formula , 5th term can be written as ;

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Putting the values and transposing 1st term to RHS , we have ;

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{: \implies \quad \sf T_{2}= T_{1}+(2-1)d}

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{: \implies \quad \sf T_{3}= T_{1}+(3-1)d}

{: \implies \quad \sf T_{3}= 8 +2d}

{: \implies \quad \sf T_{3}= 8-6}

{: \implies \quad \bf \therefore \:  T_{3}= 2}

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{: \implies \quad \sf T_{4}= T_{1}+(4-1)d}

{: \implies \quad \sf T_{4}= 8 +3d}

{: \implies \quad \sf T_{4}= 8-9}

{: \implies \quad \bf \therefore \:  T_{4}= -1}

Now , The given table can be written as ;

{\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

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