We have the given in the problem as mentioned:
A total of 130 students and only 7 had been placed in the wrong math class.
With this given, we can easily draw the proportion of all students who have been placed in the wrong math class by estimation method and the solution is shown below:
Proportion = 7/130
Answer:
Left yes
right no
Step-by-step explanation:
that goes for top and bottom
Step-by-step explanation:
a) The rule is <em><u>multiply the previous term by 6 then add 13</u></em>. So if the 1st term is n0 = -2, then the next term n1 is
n1 = 6n0 + 13
= 6(-2) + 13
= 1
n2 = 6n1 + 13
= 6(1) + 13
= 19
So the sequence goes like
-2, 1, 19
b) Now the sequence is reversed so let's write the terms as follows:
19, 1, -2
The new rule now is <em><u>subtract</u></em><em><u> </u></em><em><u>1</u></em><em><u>3</u></em><em><u> </u></em><em><u>then</u></em><em><u> </u></em><em><u>divide</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>6</u></em><em><u>.</u></em> You can check this as follows:
n0 = 19
n1 = (n0 - 13)/6
= (19 - 13)/6
= 1
n2 = (n1 - 13)/6
= (1 - 13)/6
= -2
Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
