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otez555 [7]
3 years ago
6

(3x-4)∧2=8 how do i solve this

Mathematics
1 answer:
Ber [7]3 years ago
7 0

(3x-4)^2=8\iff3x-4=\pm\sqrt8\\\\3x-4=-\sqrt{4\times2}\ or\ 3x-4=\sqrt{4\times2}\\\\3x-4=-2\sqrt2\ or\ 3x-4=2\sqrt2\ \ \ \  \ \ \ |add\ 4\ to\ both\ sides\\\\3x=4-2\sqrt2\ or\ 3x=4+2\sqrt2\ \ \ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\frac{4-2\sqrt2}{3}\ or\ x=\frac{4+2\sqrt2}{3}}
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