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Scorpion4ik [409]
2 years ago
6

What is the area of this trapezoid? 44 in² 64 in² 168 in² 192 in² Trapezoid A B C D with parallel sides D C and A B. Points F an

d E are between D and C. F E B A form a rectangle with 4 right angles. D F is 2 inches, F E is 14 inches, E C is 2 inches, A B is 14 inches., and E B is 12 inches.

Mathematics
2 answers:
hodyreva [135]2 years ago
7 0

Answer:

the answer is 192in

Step-by-step explanation:

devlian [24]2 years ago
5 0
See the attached figure

we know that
[<span>the area of the trapezoid]=[area rectangle]+2*[area triangle]
</span>[the area of the trapezoid]=[14*12]+2*[12*2/2]=192 in²

the answer is 192 in²

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Answer:

5/2

Step-by-step explanation:

In order to make the fractions equivalent, you need to place the whole number INTO the fraction itself. By doing so, your answer will be 5/2

Hope this helps :)

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I'm pretty sure its 127.8
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Answer: Hello!

ok, remember that "if and only if" implies that you need to prove the statement in both ways, this is represented with the ⇔ usually.

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In this type of problems, i  find very useful start looking for some counterexample.

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b) For any sets A, B and C, A ⊆ B ∩ C if and only if both A ⊆ B and A ⊆ C.

the first way is true; because if A ⊆ B ∩ C. then all the elements of A are in the intersection of B and C (which are common elements for B and C) and then all the elements of A are in the set B and in the set C, and this means that A ⊆ B and A ⊆ C.

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if A ⊆ B and A ⊆ C, means that all the elements of A are in B, and all the elements of A are in C, then all the elements of A are common elements between B and C, this means that B ∩ C is at least equal to A (at least, because we know that all the elements of A are common elements between B and C, but there could be more common elements that don belong to A)

then A ⊆ B ∩ C.

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