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babunello [35]
3 years ago
5

Find the perimeter of the following figure.

Mathematics
1 answer:
kompoz [17]3 years ago
5 0
Perimeter is 48
12+8+4+4+4+4+4+8=48
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This is Grade 9 Mathematics so I kinda stuck here so, if somebody can help me Please sin30⁰+csc60⁰​
mamaluj [8]

\huge\mathrm{Answer࿐}

  • \sin(30)  +  \csc(60)

  • \dfrac{1}{2}  +  \dfrac{2}{ \sqrt{3} }

  • \dfrac{ \sqrt{3 } + 4 }{2 \sqrt{3} }

To remove √3 from denominator, we multiply both numerator as well as denominator with √3

  • \dfrac{ \sqrt{3 } + 4 }{2 \sqrt{3} }  \times  \dfrac{ \sqrt{3} }{ \sqrt{3} }

  • \dfrac{3 + 4 \sqrt{3} }{6}

____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
Read 2 more answers
75 points and I’ll give brainlyist and pleas show work
IRISSAK [1]

Answer:

1. y<-2   2.  x≤5   3. 0<23    4. 0 ≤ -1   5. inequality: 3 + (7x) < 24 answer: x<3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the product (3x+8)(x-4)
timurjin [86]

Answer:

3x^{2} - 4x - 32

Step-by-step explanation:

(3x+8)(x-4)

=3x^{2} -12x + 8x -32

=3x^{2} - 4x - 32

7 0
3 years ago
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Simplify square root of negative 48.
kvv77 [185]
We want to simplify √(-48).

Note that
i² = -1 by definition.
Therefore
\sqrt{-48} =  \sqrt{i^{2}.16.3} = \sqrt{i^{2}}  \sqrt{16}  \sqrt{3} =4i \sqrt{3}

Answer: c.  4i \sqrt{3}

3 0
3 years ago
Write an equation that you can use to solve for the height of the triangle (x). Notice that the perimeter is 48 feet.
MArishka [77]
A. 48 = 12 + 20 + x

If you use this equation then you can do 12 + 20 = 32 and then you can do 48 - 32 = 16 so x = 16
7 0
3 years ago
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