Answer:

Step-by-step explanation:

what we need to do is distribute the - sign in the middle of the parentheses into (7x^2 - 7 -8x^3)[/tex], this is very important to ensure we have the correct answer. by distributing we get the following equation:

now we combine like terms to get our answer
stays as it is, since there is nothing to combine it with
7x³ + 8x³ = 15x³
3x² - 7x² = -4x²
7 stays the same because like
, there is nothing else to combine it with
we have the following new equation:

Answer:
Step-by-step explanation:
The equation shown above does not show the substitution property. Instead, it shows the Addition Property of Equation where 3 is added to both of its sides. This is shown below,
4x - 3 = 7
4x - 3 + 3 = 7 + 3
4x = 10
The graph of the pupil's score is an illustration of scatter plots
The student's expected score in paper 2 is 62
<h3>How to predict the score in the missed paper</h3>
To predict the score of the pupil in the missed paper, we simply interpret the points on the line of best fit of the scatter plot
From the graph (see attachment), we have:
Paper 2 = 62 when Paper 1 = 50
This means that the student's expected score in paper 2 is 62
Read more about scatter plots at:
brainly.com/question/6592115
Step-by-step explanation:
I think the first number is 2
Then 2 x 2 = 4 so there is a difference of 4 number
Then in between 6 and 14 there is a difference of 8 so 4 x 2 = 8
Then 16 so 8 x 2 = 16
So after 126 the number is 254
The first relation gives two y-values for any given x-value (except x=6).
y² +x = 6 . . . . . is not a function