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rosijanka [135]
3 years ago
8

Angela currently has an account balance of &4,298.55. She opened the account 15 years ago, with a deposit of $1,987.22. If t

he interest compounds monthly, what is the interest rate on the account?
Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

Answer:

The interest rate is 5.278%

Step-by-step explanation:

4298.55=1987.22(1+r/100)^15

r=5.278%

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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

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Which of the following is the balance for a single $2700 deposit in an account with an APR of 4.5% that compounds interest month
Zanzabum

The future amount is $3697.52, if a a single $2700 deposit in an account with an APR of 4.5% that compounds interest monthly and is invested for 7 years.

Step-by-step explanation:

The given is,

                     A single deposit amount - $ 2700

                                                       APR - 4.5%

                                            ( Compounded monthly )

                                                    Period - 7 years

Step:1

                 Formula to find future amount with an APR compounded monthly,

                                                          A = P(1+\frac{r}{n})^{nt}.......................(1)

                Where, A - Future amount

                             P - Initial deposit

                              r - Interest rate

                             n - Number of compounding in a year

                             t - No.of years

                From given,

                         P = $ 2700

                          r = 4.5%

                          n = 12                   (∵ For monthly n becomes 12 )

                           t = 7 years

                   Equation (1) becomes,

                                                           = 2700(1+\frac{0.045}{12})^{(12)(7)}

                                                           = 2700(1+0.00375)^{84}

                                                           = 2700(1.36945)

                                                           = 3697.52

                                                       A = $3697.52

Result:

              The future amount is $3697.52, if a a single $2700 deposit in an account with an APR of 4.5% that compounds interest monthly and is invested for 7 years.

3 0
4 years ago
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