Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
The one for 9 is 15
The one for 7 is 11
The one for 1 is -1
The one for 0 is -3
Answer:
j = 38
Step-by-step explanation:
j/-2 + 7 = -12
first subtract 7 from both sides
j/-2 = -19
then multiply both sides by -2
j = 38
Answer:
x to the third power is x cubed or x^3.
Sin 45° = opposite side / hypotenuse
1/2 = 8/h
h = 16
2)6/12 = 1/2
1/2 = sin 45°
6√3/12 = √3/2
√3/2 = cos 30°
Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°
Angles = 30° , 45° , 105°
