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3 years ago

I need help this is confusing! will mark brainliest!

Mathematics

2 answers:

marta [7]3 years ago

8 0

The answer is 15.3 I’m suer

djverab [1.8K]3 years ago

3 0

Answer:

15.333

Step-by-step explanation:

I think it's 15.3, if I've done everything correctly. Using the laws of math, you would round down, meaning that it is 15.3

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A family buys 5 airline tickets and travel insurance that costs $17 per ticket. The total cost is $850. Let x represent the pric

otez555 [7]

Answer:

850+5(x+17) (D)

153

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3 years ago

Read 2 more answers

Please answer, Thank you. Image below.

Bezzdna [24]

Answer:

88°

Step-by-step explanation:

The triangle is an isosceles triangle, so two of the angles are both 46°. We also know that the sum of all the angles in any triangle is 180°, so we can set up the following equation:

46° + 46° + e = 180°

Solving this gets e = 88°.

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2 years ago

I need to know the answer to this?

iris [78.8K]

Answer:

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3 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

4 years ago

-4x+3 >-5 Solve for a

Tresset [83]

Answer:

-4x+3>-5

or, -4x>-5-3

or, -4x>-8

or, -4x/-4<-8/-4

so, x<2

4 0

2 years ago