Question 16 and 17 please

Mathematics

1 answer:

Elza [17]3 years ago

3 0

Answer:

16. Yes

17. Yes

Step-by-step explanation:

Since the angles are congruent (due to parallel lines) the two triangles are similar. Similar triangles form congruent ratios between their corresponding sides.

Since the quadrilaterals are similar, this means the angles in each are congruent. This will not change when divided by diagonals. The triangles in each will have congruent angles and their sides will maintain equivalent ratios.

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Using the line ab name two line segments<br> Brainliest

ohaa [14]

Answer:

A. AC, CB

Step-by-step explanation:

The answer you have selected is correct because a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints. Thus the answer A is correct!

Hope this helps

All the love, Ya boi Fraser :)

7 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: