The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have
The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have
The second sum is simply the sum of N ones:
So, the final result is
which ends the proof.
Answer: Yes
Step-by-step explanation:
It is a relation because each person will most likely have a different name and you can have plenty of the same outputs just as long as the input doesn't repeat at all.
Attention:THIS IS PART B <em>ONLY!</em>
First,find the unit rate.
35/2 and <em>x</em>/1
35 divided by 2 = 17.5 so the unit rate for J.K. is 17.5 pages per hour.
now,R.L.
45/3 and <em>x</em>/1
45 divided by 3 = 15 so the unit rate for R.L. is 15 pages per hour
now we need to divide 355 by 17.5 and divide it by 15.Whichever quotient is smaller,finishes the book first
355 divided by 17.5 = about 20 hrs----J.K.
355 divided by 15 = about 24 hrs-----R.L.
So,who read faster?
(3^3)* (3^-3)= 3^0
Remember that if you have the same base, add the exponents.
3^0=1
5(1)=5
Final answer: 5