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Mashcka [7]
3 years ago
10

Subtracting 3x^2+4x-5 from 7x^2+x+9

Mathematics
1 answer:
Helga [31]3 years ago
8 0
7x^2+x+9 - (<span>3x^2+4x-5)
= </span>7x^2 + x + 9 - 3x^2 - 4x + 5
= 4x^2 - 3x + 14
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3 years ago
A rigid transformation can also be referred to as an
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Answer:

See below.

Step-by-step explanation:

A rigid transformation changes the position of the object but not the size. Since the size remains the same, the transformation is isometric, meaning the same measure, or same size.

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Solve for b.
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One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
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Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

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So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

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\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

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3 years ago
The volume of a cylinder that has a length of 13 and radius of 20
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Answer:

36756.63 un³

Step-by-step explanation:

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