4 to 7
or
4+7= 12
4x+7x=33
x=3
so,
(4×3)+(7×3)=33
12+21=33
or
12 and 21.
hope it helped
Answer:
2x+5=4x+1
5=2x+1
4=3x
x=1.3333333 or 1 1/3
Step-by-step explanation:
First of all you rearrange the problem so that the same variables are together (remember to keep the sign in-front of the coefficient with it)...
This would make the problem look like...
4<u>x^2</u> / 8<u>x^2</u> * 4<u>x^2</u> /2<u>x^2</u> -<em>y^2 + 3y^2 + 4y^2 </em>+ 10xy - 9xy - 5xy
Now you would simplify the coefficients based upon the variable...
<u /><u>x^2</u> <em>- 10y^2 </em>- 4xy<em>
<u>Hope this helps!</u> :)</em><em>
</em>
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
