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asambeis [7]
3 years ago
6

How do you solve the equation 9/14=-2

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer: the equation is false

Step-by-step explanation:

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Find the value of the expression 4a4 − 2b2 + 40 when a = 2 and b = 7.
Makovka662 [10]
4 a⁴ - 2 b² + 40 :

4 * ( 2⁴) - 2  * ( 7²)  + 40 = 

4 * 16 - 2 * 49 + 40 =

64 - 98 + 40 =

-34 + 40 =

+ 6

<span>hope this helps!</span>
4 0
3 years ago
jamerra received a $3,00 car loan. she plans on paying off the loan in 2 years. at the end of 2 years, jamerra will have paid $4
leonid [27]

The rate of interest is 75 % per year

<em><u>Solution:</u></em>

Given that, Jamerra received a $3,00 car loan

she plans on paying off the loan in 2 years

<em><u>Jamerra will have paid $450 in interest</u></em>

Therefore, we get

Principal = $ 300

Number of years = 2

Simple Interest = $ 450

Rate of interest = ?

<em><u>The simple interest is given by formula:</u></em>

simple\ Interest = \frac{p \times n \times r}{100}

Where,

"p" is the principal and "n" is the number of years and "r" is the rate of Interest

<em><u>Substituting the given values we get,</u></em>

450 = \frac{300 \times 2 \times r}{100}\\\\450 = 3 \times 2 \times r\\\\6r = 450\\\\r = \frac{450}{6}\\\\r = 75

Thus rate of interest is 75 % per year

5 0
3 years ago
Jan received -22 points on her exam. She got 11 questions wrong out of 50 questions. How much was Jan penalized for each wrong a
svp [43]
2 points for each incorrect answer.
6 0
3 years ago
Read 2 more answers
Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,
Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j}  = {(1,0), (0,1)}

is a base in \mathbb{R}^2

and F is linear, then

<em>{F(1,0), F(0,1)}  </em>

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0
3 years ago
Can some one help me with this question its hard :( down below ill give brainliest
tresset_1 [31]

Answer:

B) 7^2 x 7^3

Step-by-step explanation:

B is 7^5 , everything else is 7^4

6 0
3 years ago
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