Answer:
0.33 mol of Fe₂O₃
Explanation:
For the reaction given in the question -
Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂
Balancing the above reaction ,
2Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂
According to the above balanced reaction ,
<u>2 mol of Fe₂O₃ will react with 5 mol of C and 3 mol of O₂ to give 2 mol of Fe and 5 mol of CO₂ .</u>
Hence ,
2 mol of Fe₂O₃ will react with 3 mol of O₂
or ,
3 mol of O₂ ------ 2 mol of Fe₂O₃
Using unitary method ,
1 mol of O₂ ------ 2 / 3 mol of Fe₂O₃
From the question , for 0.49 mol of O₂ ,
0.49 mol of O₂ ------- 2 / 3 * 0.49 mol of Fe₂O₃ = 0.33 mol of Fe₂O₃
I believe it is a solution but I am not Shure
The last one, add the labels on the x and y axis
Answer : The millimoles of acetate need to add to this solution will be, 18.2 mmol
Explanation :
For acetic acid, ![pK_a=4.74](https://tex.z-dn.net/?f=pK_a%3D4.74)
Moles of of acetic acid = 10 mmol
pH = 5.00
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:
![5.00=4.74+\log (\frac{Salt}{10})](https://tex.z-dn.net/?f=5.00%3D4.74%2B%5Clog%20%28%5Cfrac%7BSalt%7D%7B10%7D%29)
![Salt=18.2mmol](https://tex.z-dn.net/?f=Salt%3D18.2mmol)
Thus, the millimoles of acetate need to add to this solution will be, 18.2 mmol
Answer:
Budding- A new organism growing from the body of the parent
Fragmentation- The parent breaks into parts that may regenerate into offspring
Binary Fission- The parent cell divides to produce a genetically identical cell