All categories

3 years ago

Fe2O3 + 5C + 3O2 = 2Fe + 5CO2

Chemistry

1 answer:

tangare [24]3 years ago

3 0

Answer:

0.33 mol of Fe₂O₃

Explanation:

For the reaction given in the question -

Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

Balancing the above reaction ,

2Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

According to the above balanced reaction ,

<u>2 mol of Fe₂O₃ will react with 5 mol of C and 3 mol of O₂ to give 2 mol of Fe and 5 mol of CO₂ .</u>

Hence ,

2 mol of Fe₂O₃ will react with 3 mol of O₂

or ,

3 mol of O₂ ------ 2 mol of Fe₂O₃

Using unitary method ,

1 mol of O₂ ------ 2 / 3 mol of Fe₂O₃

From the question , for 0.49 mol of O₂ ,

0.49 mol of O₂ ------- 2 / 3 * 0.49 mol of Fe₂O₃ = 0.33 mol of Fe₂O₃

You might be interested in

A. A student was given an unknown sample of a pure metal to identify. Its mass was 116

forsale [732]

Answer:

Silver

Explanation:

Given parameters:

Mass = 116g

Energy = 511J

Initial temperature = 21.6°C

Final temperature = 40.5°C

Unknown:

Specific heat capacity and the type of metal = ?

Solution:

To solve this problem, we need to find the specific heat capacity of the metal given,

H = m x c x Ф

H is the energy

m is the mass

c is the specific heat capacity

Ф is the change in temperature

511 = 116 x c x (40.5 - 21.6)

511 = 2192.4c

c = 0.233J/g°C

The specific heat capacity of silver is similar to this.

3 0

3 years ago

Write down the Classification of a Molecule.

galina1969 [7]

Answer:

smallest unit element are made of

6 0

3 years ago

The initial volume of HCl was 1.25 ml and LiOH was 2.65 ml. The final volume of HCL was 13.60 ml and LiOH was 11.20 ml. If the L

Dennis_Churaev [7]

Q1)
This is a strong acid- strong base base reaction, balanced equation for the reaction is as follows;
LiOH + HCl ---> LiCl + H₂O
stoichiometry of acid to base is 1:1
volume of HCl used up - 13.60 - 1.25 = 12.35 mL
volume of LiOH used up - 11.20 - 2.65 = 8.55 mL
molarity of LiOH - 0.140 M
The number of LiOH moles reacted - $\frac{0.140 mol/L*8.55mL}{1000mL}$ = 0.001197 mol
according to stoichiometry, number of LiOH moles = number of HCl moles
Therefore number of HCl moles reacted - 0.001197 mol
The number of HCl moles in 12.35 mL - 0.001197 mol
Then number of HCl moles in 1000 mL - $\frac{0.001197*1000mL}{12.35mL}$
Molarity of HCl - 0.0969 M

Q2)
Volume of HCl used - 12.35 mL
Volume of LiOH used - 8.55 mL
Molarity of HCl - 0.140 M
In 1 L solution of HCl there are 0.140 mol of HCl
Therefore number of HCl moles in 12.35 mL - $\frac{0.140mol*12.35 mL}{1000mL}$
Number of HCl moles reacted - 0.001729 mol
since molar ratio of acid to base is 1:1
the number of LiOH moles that reacted - 0.001729 mol
Therefore number of moles in 8.55 mL - 0.001729
Then number of LiOH moles in 1000 mL - $\frac{0.001729mol*1000mL}{8.55 mL}$
molarity of LiOH - 0.202 M

5 0

3 years ago

Determine the number of HC=CH, monomeric units in one molecule of polyethylene with a molar

VladimirAG [237]

polyethylene contains HC=CH units.

mass of this is 26 gram/mol

number of such units =13500/26

3 0

4 years ago

Which of the following would force the reaction to favor the products? CaCO3(s) + 2H3O(aq) + Ca(aq) + 3H2O(1) + CO2(g) A) Removi

iVinArrow [24]

Answer: Option (C) is the correct answer.

Explanation:

As the given reaction is as follows.

$CaCO_{3}(s) + 2H_{3}O^{+}(aq) \rightleftharpoons Ca^{2+}(aq) + 3H_{2}O(l) + CO_{2}(g)$

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

Hence, in order to favor the formation of products when we remove $CO_{2}$ then there will occur decrease in it's concentration.

As $CO_{2}$ is forming on the product side and equilibrium will shift in the direction where there is less stress.

Hence, then equilibrium will shift in the forward direction, that is, on the products side.

Thus, we can conclude that removing $CO_{2}$ as it is formed would force the reaction to favor the products.

3 0

3 years ago