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olga nikolaevna [1]
3 years ago
15

Which equation correctly applies the distributive property?

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

hello there how are you today

you awnser is A and C they both apply

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Shown here is a frequency distribution for the rise in tides at 30 selected locations in the U.S.Find the variance and standard
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It’s is going to be 15 since 30/2 equals 15
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3 years ago
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If (x^2−1)/(x+1) = 3x + 5, then x + 3 =<br> (A) -3<br> (B) -2<br> (C) 0<br> (D) 2<br> (E) 4
sineoko [7]
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3 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
3 years ago
The sprocket on the crankshaft of an engine power the camshaft by a chain assembly. If the engine crankshaft is turning 3250 rev
Lera25 [3.4K]

Answer:

  • 30,631 inches
  • 2553 feet

Step-by-step explanation:

The length of one revolution of the sprocket is ...

  C = 2πr = 2π(1.5 in) = 3π in

Then the length of 3250 revolutions is ...

  3250(3π in) = 30,630.53 in

About 30,631 inches of chain travel past the sprocket in one minute.

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There are 12 inches in a foot, so the number of feet is ...

  30,630.53 in/(12 in/ft) = 2552.54 ft

About 2553 feet of chain travel past in one minute.

8 0
3 years ago
Please help me with this question
maw [93]
The answer is b with the angles
8 0
3 years ago
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