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Naddika [18.5K]
3 years ago
10

The formula for the volume of a rectangular prism is V = lwh. Which is the equivalent equation solved for h?​

Mathematics
1 answer:
wel3 years ago
4 0

Answer:

V /(lw) = h

Step-by-step explanation:

V = lwh

Divide each side by lw

V/ ( lw) = lwh/(lw)

V /(lw) = h

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Write a quadratic function h whose zeros are 5 and -7
marin [14]

Quadratic function whose zeros are 5 and -7 is x^2+2x-35=0

Step-by-step explanation:

Write a quadratic function h whose zeros are 5 and -7

If 5 and -7 are zeros of quadratic function then:

x=5 and x=-7

or x-5 = 0 and x+7=0

So, Finding quadratic equation:

(x-5)(x+7)=0\\x(x+7)-5(x+7)=0\\x^2+7x-5x-35=0\\x^2+2x-35=0

So, quadratic function whose zeros are 5 and -7 is x^2+2x-35=0

Keywords: Quadratic Function

Learn more about Quadratic Function at:

  • brainly.com/question/7361044
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#learnwithBrainly

3 0
3 years ago
Find m∠ABD and m∠CBD given m∠ABC = 111∘
Y_Kistochka [10]

Answer:

The is the m ∠ABC = m∠DEF the measures of the angles are equal ... Find the measure of the angle and give the reason for knowing it. ... x = __111___ ... m∠ABD = 3x + 20 and m∠BDC = x + 40 ... an equation to solve for x, and then find

AB, CD,. Hope It Helps!

7 0
3 years ago
A Ladder that is 32 ft long leans against a building. The angle of elevation of the ladder is 70 degrees. To the nearest tenth o
kolezko [41]
See the picture attached to better understand the problem

we know that
in the right triangle ABC
sin 70°=opposite side angle 70°/hypotenuse


in this problem
opposite side angle 70°=AB
hypotenuse=AC----> 32 ft
sin 70°=AB/32------> AB=32*sin 70°-----> AB=30.07 ----> AB=30.1 ft


4 0
3 years ago
Read 2 more answers
Can anyone please help??
Igoryamba
There are infinite numbers

7 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
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