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Sloan [31]
3 years ago
12

Find the circumference of the circle. A circle has diameter 9 centimeters. 9

Mathematics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

2.86478897565  or   3 (if rounded to the nearest whole number)

Step-by-step explanation:

How we find circumference by using diameter is divide the diameter by pi

SO 9 divide by pi equals 2.86478897565 or 3 (if rounded to the nearest whole number)

Can u mark me as brainlist? :)

HAVE A GREAT DAY!

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MrRa [10]
I belive the answer to be b
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3 years ago
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Figure out the pattern, fill in the blank square.
Cloud [144]

Answer:448

Step-by-step explanation:

So to start,you can see that 8 times 2 is 16.And 16 times 4 is 64.So the pattern is times 2 then times 4 then times 6.On the edges you can see 64.You multiply 64 by 6 and you get 384.Then you multiply 8 times 6 that equals 48.And you multiply 4 times 4 and get 16.After you add 384 and 48 which equals 432.And then your done.(I think that's the answer)

3 0
3 years ago
Solve this
sesenic [268]

A sandwich store charges a delivery fee to bring lunch to an office.

Delivery cost - D

Meatball sandwich cost  - M

One office pays $40.50 for 5 meatball sandwiches.

40.50 = 5M + D

Another office pays $66.50 for 9 meat ball sandwiches

66.50 = 9M + D

A. How much does each meatball sandwich add to the cost of delivery?

D = 40.50 - 5M = 66.50 - 9M

40.50 - 5M = 66.50 - 9M

9M - 5M = 66.50 - 40.50

4M = 26.00

M = 6.50

B. What is the delivery fee

D = 40.50 - 5M = 40.50 - 5(6.50) = 40.50 - 32.50 = 8.00

Check

66.50 = 9M + D = 9(6.50) + 8 = 58.50 + 8.00 = 66.50

3 0
3 years ago
Uhhhhhmmmmmmmmmmmm wuts dis
vichka [17]

Answer:

Hey!

Step-by-step explanation:

Your answer would be 1/8

Have a nice day!♥

And ty XD

8 0
3 years ago
A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has
bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113  

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711  

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] =  1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0
3 years ago
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