Solve for “x” -10 = -x^2 + 2x

It is believed that 3% of people actually have this predisposition. The genetic test is 99% accurate if a person actually has th

fiasKO [112]

Answer:

Required Probability = 0.605

Step-by-step explanation:

Let Probability of people actually having predisposition, P(PD) = 0.03

Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97

Let PR = event that result are positive

Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99

Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02

So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)

Using Bayes' Theorem to calculate above probability;

P(PD/PR) = $\frac{P(PD)*P(PR/PD)}{P(PD)*P(PR/PD)+P(PD')*P(PR/PD')}$

= $\frac{0.03*0.99}{0.03*0.99+0.97*0.02}$ = $\frac{0.0297}{0.0491}$ = 0.605 .

7 0

3 years ago

For a craft, each student will need five rubber bands. There are eight students. What rubber bands come in bags of 9. How many b

gizmo_the_mogwai [7]

Answer:

In total 5 packets of rubber bands are needed.

Out of which 5 rubber bands are left.

Step-by-step explanation:

The number of rubber bands needed by 1 student = 5

The total number of students = 8

So, the total rubber bands needed by all students

= Total students x Number of rubber bands needed by 1 student

= 8 x 5 = 40 bands

Now 1 packet of rubber bands = 9 bands

⇒ 2 packets = 2 x ( 9 bands) = 18 bands

⇒ 3 packets = 3 x ( 9 bands) = 27 bands

Similarly, 4 packets = 36 bands , 5 packets = 45 bands

Now, if we buy 4 packet of bands, there are 36 rubber bands which are LESS THAN THE TOTAL STUDENTS.

So, we buy 5 packets.

We have in total 45 bands, but the total students = 40

So, the number of left rubber bands = Total bands - Total students

= 45 - 40 = 5

Hence, in total 5 packets of rubber bands are needed, and out of which 5 rubber bands are left.

5 0

3 years ago

If

strojnjashka [21]

$p + q = \frac{2u}{1 - u} + \frac{1 + u}{1 - u} = \frac{1 + 3u}{1 - u}$

$p - q = \frac{2u}{1 - u} - \frac{1 + u}{1 - u} = \frac{u - 1}{1 - u}$

$\frac{p + q}{p - q} = \frac{1 + 3u}{1 - u} \div \frac{u - 1}{1 - u} = \frac{1 + 3u}{1 - u} \div (- 1) = - \frac{1 + 3u}{1 - u}$

5 0

4 years ago

Find the area of a parallelogram: base 5.2 cm, height 2.3 cm. 10.6 cm² 12.96 cm² 5.98 cm² 11.96 cm² I think its the last option

Alinara [238K]

$base : \ a =5.2 \ cm, \ \ height : \ 2.3 \ cm \\ \\ Area = a\cdot h = 5.2\cdot 2.3 =11.96 \ cm^2 \\ \\ Answer: \ Area = 11.96 \ cm^2$

8 0

3 years ago

Process of substitution <br> y=2x-4<br> 4x+5y=22

Dima020 [189]

Answer:

X=3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve for “x” -10 = -x^2 + 2x - 6