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Ksenya-84 [330]
2 years ago
9

What is the slope of a line perpendicular to the line whose equation is 3x-3y=54. Fully simplify your answer.​

Mathematics
1 answer:
padilas [110]2 years ago
7 0
Perpendicular = opposite sign and reciprocal slope
Make equation into y = mx + b
Add 3y to both sides
3y + 54 = 3x
Subtract 54
3y = 3x - 54
Divide by 3
y = x - 18
The slope is 1
Make it negative and reciprocal
= -1/1 = -1

Solution: the slope will be -1
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40/100 is 40%
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3 years ago
1) y=-3x + 4 y = 3x - 2 (1,1)​
puteri [66]

Answer:

y=3x-2

Step-by-step explanation:

your question didn't have any instructions so this might not be what you're looking for

set them equal to each other

-3x+4=3x-2

-3x-3x=-2-4

-6x=-6

x=1

plug in x=1

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Step-by-step explanation:

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6 0
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Given: Quadrilaterals ABCD ~ EFGH , with measure of angle A = 47 degrees, measure of angle B = 39 degrees, and measure of angle
kaheart [24]

Answer:

The answer is below

Step-by-step explanation:

Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.

Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.

In quadrilateral ABCD:

∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)

Substituting:

47 + 39 + 112 + ∠D = 360

∠D + 198 = 360

∠D = 360 - 198

∠D = 162°

The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:

∠A = ∠E = 47°

∠B = ∠F = 39°

∠C = ∠G = 112°

∠D = ∠H = 162°

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Answer: Venus

Step-by-step explanation:

5 0
2 years ago
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