Question

Evaluate g(n-7) if g(x) =x^2-5 / 3x

Answer 1

Answer:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

Step-by-step explanation:

The given function is

$g(x)=\frac{x^2-5}{3x}$

To find g(n-7), we substitute x=n-7 to obtain;

$g(n-7)=\frac{(n-7)^2-5}{3(n-7)}$

Expand the parenthesis to obtain;

$g(n-7)=\frac{n^2-14n+49-5}{3n-21}$

Simplify:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$