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3 years ago

7

One number is one-fifth of another number. The two numbers total 18. Find the numbers

1 answer:

Masja [62]3 years ago

8 0

Answer:

One number is 17 and the other is 85.

Step-by-step explanation:

Let the numbers be m and n. Let m = (1/5)n. Note that m+n = 18.

Substituting (1/5)n for m in the 2nd equation, we get (1/5)n + (5/5)n = 18. Multiplying all three terms by 5 to remove fractions, we get n + 5 = 90, so that n = 85. m is (1/5) of 85, or m = 17.

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rusak2 [61]

Answer:

6 cm^3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The sum of two consecutive integers is 139, find the integers.

Ad libitum [116K]

They would be 69 and 70.

Your equation would be x + (x + 1) = 139

X would be the first integer and x + 1 would be the second

You would then solve the equation to get x as 69

X + 1 would then be 70

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3 years ago

Help! <br> Which expression is equivalent? <br> On edge

Ira Lisetskai [31]

Answer: Choice B

$x^{1/8}y^{8}$

======================================================

Explanation:

The two rules we use are

$(a*b)^c = a^c*b^c$

$(a^b)^c = a^{b*c}$

When applying the first rule to the expression your teacher gave you, we can say that:

$\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}$

Then applying the second rule lets us say

$\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}$

Therefore,

$\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}$

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

7 0

3 years ago

Evaluate the following expression:<br> -X- 6x + 10 when x = 5

BigorU [14]

Answer:

-25

Step-by-step explanation:

Evaluate -x - 6 x + 10 where x = 5:

-x - 6 x + 10 = -5 - 6×5 + 10

-6×5 = -30:

-5 + -30 + 10

-5 - 30 + 10 = 10 - (5 + 30):

10 - (5 + 30)

5 + 30 = 35:

10 - 35

10 - 35 = -(35 - 10):

-(35 - 10)

| 3 | 5

- | 1 | 0

| 2 | 5:

Answer: -25

8 0

3 years ago

Find f(4) when f(x)=4x^2 - 2 x - 4

prisoha [69]

Answer:

52

Step-by-step explanation:

$f(x)=4x^2-2x-4$

$f(4)=4(4)^2-2(4)-4$ (I replaced $x$ with $(4)$ since we are to find $f(4)$ .)

$f(4)=4(16)-2(4)-4$ (By the order of operations, we take care of the exponents before whatever else we have here.)

$f(4)=64-8-4$ (By the order of operations, we take care of the multiplication as we see if left to right.)

$f(4)=56-4$ (By the order of operations, we perform addition/subtraction as we see it left to right.)

$f(4)=52$ (This completes the simplification.)

We could have also put this in our calculator as:

4(4)^2 - 2(4) - 4

This would have returned 52.

8 0

3 years ago