Answer:
below
Step-by-step explanation:
that is the procedure above
Answer:
2, 3
Step-by-step explanation:
If the first integer is x, then the second is x+1. The given relation is ...
x +3(x+1) = 11
4x = 8 . . . . . . . . subtract 3
x = 2 . . . . . . . divide by 4
The integers are 2 and 3.
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<em>Check</em>
2 + 3(3) = 2+9 = 11
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
The answer is D
Step-by-step explanation:
8484.79-4854=3,630.79,,3630.79=4854*17 r,,r=4.4%
