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3 years ago

What is the area of this trapezoid?

Mathematics

1 answer:

alukav5142 [94]3 years ago

8 0

Answer:

A=0.5(a+b)h

=0.5(27+17)4=88units^2

Step-by-step explanation:

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Connor wants to drive from Tucson to the Grand Canyon a distance of 338 miles if he drives a steady rate of 52 mph how many hour

alexandr1967 [171]

Answer:

6.5 Hours

Step-by-step explanation:

Divide 338 by 52 to get the answer

5 0

3 years ago

Mr Daniels is organizing a class field trip on a budget of $900.The bus rental costs $600. Mr.daniels will also buy tickets that

solmaris [256]

600 + 9.5x (less than or equal to) 900

600 fixed amount
9.5 is the variable changing amount and differs among number of students taken

8 0

3 years ago

Read 2 more answers

You need to buy tissue paper sheets to cushion gifts being placed inside a box. The box is 12 inches wide by 16 inches long. The

Kay [80]

Answer:

Area of tissue paper is 384 square inches.

Step-by-step explanation:

Given:

Length of box = 16 inches.

Width of the box = 12 inches.

We need to find find the area of the tissue paper.

But It is given that the area of the tissue paper sheet is based on twice the length times the width of the box.

Hence Framing in equation form we get;

Area of tissue paper = $2(length\ of \ box \times width \ of \ box)$

Hence Substituting the given values we get;

Area of tissue paper = $2(12\times 16) = 2\times 192 = 384 in^2$

Hence Area of tissue paper is 384 square inches.

7 0

3 years ago

Plsss help answer the question don’t just get the points and not answer my question Plss I’m struggling

Shkiper50 [21]

Answer:

This is cheating

Step-by-step explanation:

First you follow what your teachers tell you to do and listen

6 0

3 years ago

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

4 years ago