The addition of the function is:
(f+g)(x)= f(x)+g(x)
So, (f+g)(5)= f(5)+g(5)
To find f(5) and g(5), plug in 5 for x in both the functions.
So, f(5)= 8(5)-13 = 40-13 = 27
g(5)= 5-9= -4
Now we can add f(5) and g(5) to get the answer.
So, (f+g)(5)= 27 +(-4) = 27-4= 23
Hence, (f+g)(5)= 23
Equations don't have minimum or maximum, functions do.
Function y=2n^2+5n-25 has minimum -28.125, has no maximum.
The sequence
1, 3, 7, 13, 21, ...
has first-order differences
2, 4, 6, 8, ...
Let
denote the original sequence, and
the sequence of first-order differences. It's quite clear that

for
. By definition of first-order differences, we have

for
, or

By substitution, we have






and so on, down to

You should know that

and we're given
, so

or

Alternatively, since we already know the sequence is supposed to be quadratic, we can look for coefficients
such that

We have



and we can solve this system for the 3 unknowns to find
.
Answer:
there are 5 roots,
Step-by-step explanation:
Answer:
I don't knoe
Step-by-step explanation:
thanks for the question but I couldn't answer it