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r-ruslan [8.4K]
4 years ago
10

Triangle ABC has vertices at A(3, 8) , B(11, 8) , and C(7, 12) . Triangle FGH has vertices at F(8, 4) , G(16, 4) , and H(12, 8)

. Which sequence of transformations shows that triangle ABC and triangle FGH are congruent? Select each correct answer. Translate ​ triangle ABC ​ down 4 units, and then translate ​ triangle ABC right 5 units. Translate ​ triangle FGH ​ down 4 units, and then translate ​ triangle FGH ​ left 5 units. ​ Translate ​ triangle FGH ​ up 4 units, and then translate ​ triangle FGH ​ left 5 units. ​ Translate ​ triangle ABC ​ down 4 units, and then translate ​ triangle ABC ​ left 5 units.

Mathematics
2 answers:
lisov135 [29]4 years ago
5 0

This the answer hope it helps!!

KiRa [710]4 years ago
3 0
Vertices of ΔABC 
A - <span>(3, 8)
</span><span>B - (11, 8)
C - (7, 12)
vertices  of </span>Δ<span>FGH
F - (8, 4)
G - (16, 4)
H - (12, 8) 
after a translation the size nor shape of the triangle changes, every point of the triangle moves the same distance in the same direction. 
if we take point A and F
x coordinates of A = 3 and F = 8
the change that has happened can be noted as 'm'
3 + m = 8
m = 5
this means that the point has moved 5 units to the right
y coordinates of A = 8 and F = 4
change that happened is 'n'
8 + n = 4
n = -4
this means that point has moved 4 units downwards

Therefore the correct answer is </span><span>Translate ​ triangle ABC ​ down 4 units, and then translate ​ triangle ABC right 5 units</span>
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When Ximena commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 38 minutes and a
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Answer:

The interval that represents the middle 68% of her commute times is between 33.5 and 42.5 minutes.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 38 minutes, standard deviation of 4.5 minutes.

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Within 1 standard deviation of the mean. So

38 - 4.5 = 33.5 minutes

38 + 4.5 = 42.5 minutes.

The interval that represents the middle 68% of her commute times is between 33.5 and 42.5 minutes.

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Past studies have indicated that the percentage of smokers is estimated to be about 35%. Given the new smoking cessation program
aleksandr82 [10.1K]

Answer:

H0: p = 3.5

H1: p < 3.5

Step-by-step explanation:

We are told that past studies have indicated that the percentage of smokers is estimated to be about 35%, but with the new smoking cessation programs that have been implemented, it is believed that the percentage of smokers has been reduced, we must propose our null and alternative hypotheses, which would be the following:

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Consider the experiment where a pair of fair dice is thrown. Let X denote the random variable whose value is determined by takin
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Answer:

Pr(X=1) = 1/36

Pr(X=2) = 3/36

Pr(X=3) = 5/36

Pr(X=4) = 7/36

Pr(X=5) = 9/36

Pr(X=6) = 11/36

Pr(X is divisible by 4) = 7/36

Step-by-step explanation:

Two fair die are thrown and X = maximum of the two die.

Pr(X=1) means 1 is the maximum number of the two numbers showing on the dice. This can only happen when both dice are showing 1. So,

Pr(X=1) = (1,1)

          = (1/6)*(1/6)

Pr(X=1) = 1/36

Pr(X=2) = (1,2) + (2,1) + (2,2)

            = (1/6)*(1/6) + (1/6)*(1/6) + (1/6)*(1/6)

Pr(X=2) = 3/36

Pr(X=3) = (1,3) + (2,3) + (3,1) + (3,2) + (3,3)

            = (1/6)*(1/6) + (1/6)*(1/6) + (1/6)*(1/6) + (1/6)*(1/6) + (1/6)*(1/6)

Pr(X=3) = 5/36

Pr(X=4) = (1,4) + (2,4) + (3,4) + (4,1) + (4,2) + (4,3) + (4,4)

            = (1/6)*(1/6)+(1/6)*(1/6)+(1/6)*(1/6)+(1/6)*(1/6)+(1/6)*(1/6)+(1/6)*(1/6)+(1/6)*(1/6)

Pr(X=4) = 7/36

Pr(X=5) = (1,5) + (2,5) + (3,5) + (4,5) + (5,1) + (5,2) + (5,3) + (5,4) + (5,5)

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Pr(X=5) = 9/36

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            = 11 * (1/6)*(1/6)

Pr(X=6) = 11/36

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Pr(X is divisible by 4) = Pr(X=4)

Pr(X is divisible by 4) = 7/36

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