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patriot [66]
3 years ago
12

Complete the paragraph proof. Given: and are right angles Line segment A B is-congruent-to line segment B C Line segment B C is-

congruent-to line segment A C Prove: Line A R bisects Angle B A C Triangles A B R and R C A share side R A. A line is drawn from point B to point C and intersects side A R at point P. It is given that and are right angles, and . Since they contain right angles, ΔABR and ΔACR are right triangles. The right triangles share hypotenuse , and reflexive property justifies that . Since and , the transitive property justifies . Now, the hypotenuse and leg of right ΔABR is congruent to the hypotenuse and the leg of right ΔACR, so by the HL congruence postulate. Therefore, ________ by CPCTC, and bisects by the definition of bisector.
Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

<BAR ≅<CAR

Step-by-step explanation:

Just took the test

anygoal [31]3 years ago
5 0

Answer:

A edg 2020

Step-by-step explanation:

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C 152

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Beacuse it is. Hope that helps

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SOLVE THIS PROBLEM ASAP PLS
Drupady [299]
6785 - 6496 = 289 units
289 x 13p = 3757p
3757p = £37.57
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A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;upstream&100&b-c&5\\&#10;downstream&100&b+c&2&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;100=(b-c)5\\&#10;\qquad \frac{100}{5}=b-c\\&#10;\qquad 20=b-c\\&#10;\qquad 20+c=\boxed{b}\\&#10;100=(b+c)2\\&#10;\qquad 50=b+c\\&#10;\qquad 50=\boxed{20+c}+c&#10;\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
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3 years ago
Square root for 9/100
Leno4ka [110]

\sqrt{a}=b\iff b^2=a\ for\ a\geq0\ and\ b\geq0.\\\\\sqrt{\dfrac{9}{100}}=\dfrac{\sqrt9}{\sqrt{100}}=\dfrac{3}{10}

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3 years ago
Expanded form for 13 cubed
saw5 [17]
The answer to this question is 2197! Hope this helped :3
5 0
3 years ago
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