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patriot [66]
3 years ago
12

Complete the paragraph proof. Given: and are right angles Line segment A B is-congruent-to line segment B C Line segment B C is-

congruent-to line segment A C Prove: Line A R bisects Angle B A C Triangles A B R and R C A share side R A. A line is drawn from point B to point C and intersects side A R at point P. It is given that and are right angles, and . Since they contain right angles, ΔABR and ΔACR are right triangles. The right triangles share hypotenuse , and reflexive property justifies that . Since and , the transitive property justifies . Now, the hypotenuse and leg of right ΔABR is congruent to the hypotenuse and the leg of right ΔACR, so by the HL congruence postulate. Therefore, ________ by CPCTC, and bisects by the definition of bisector.
Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

<BAR ≅<CAR

Step-by-step explanation:

Just took the test

anygoal [31]3 years ago
5 0

Answer:

A edg 2020

Step-by-step explanation:

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A hammock that hangs between two trees makes a parabola shape that has the equation y = 0.4(x- 3)² +1, where x is the distance f
34kurt

Answer:

A. The lowest point of the hammock is at the point 1 meters above the ground and 3 meters from one end of the hammock

B. The two trees are 6 meters away from one another

Step-by-step explanation:

The given equation of the parabola representing the hammock is as follows;

y = 0.4·(x - 3)² + 1

The general equation of a parabola is a·(x - h)² + k;

Where the coordinates of the vertex point of the parabola, which is the lowest (or highest, furthest) point on the vertex is (h, k) = (3, 1)

Therefore, we have;

A, The coordinates of the lowest point on the hammock is (3, 1)

Therefore, the lowest point of the hammock is at 1 meters above the ground and 3 meters from one end of the hammock

B.  Given that the distance from one end is "x", we have;

The height at which the hammock is attached is given as the point where x = 0 as follows;

Given that the vertex of the parabola represents the axis of symmetry of the parabola, we have that the horizontal distance from one end of the hammock to the vertex point of the parabola that the hammock forms is (3 - 0) meters = 3 meters

Therefore, by the definition of symmetry, the distance from the vertex point to the other end of the parabola that the hammock forms is also 3 meters

From which we have, the distance the two trees are from one another is 3 meters + 3 meters = 6 meters.

4 0
2 years ago
A.Pet owners may have to take out a loan when their animal has a major operation. Buddy needs to have a surgery on his leg. The
jeyben [28]
$2,500 • 7.5% (or 0.075) = $187.50 (for one year).

For two years, the interested added onto the original price is $375 because $187.50 • 2 (years) = $375.

$2,500 + $375 = $2,875

The total of the cost of the surgery and the interest is $2,875.

Hope this helps! ❤️
3 0
3 years ago
The scale of a map is 1 in. = mi. Find each length on the map
WITCHER [35]

The question gives the relationship to be

1in=21mi

We will interpolate to solve the question.

First Question: 147 mi

\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}

Cross multiplying,

undefined

7 0
1 year ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
Item 5 Use the axis of symmetry to find the reflection of each point. The reflection of (−3,−3) ( − 3 , − 3 ) is (, ). The refle
GenaCL600 [577]

Answer:

dddddddddddddddddddddddd

Step-by-step explanation:

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4 0
2 years ago
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