1a:
580 - (580 × .1) - 20
580 - (58) - 20
522 - 20
502
1b:
990 - (990 × .25) - 20
990 - (247.5) - 20
742.5 - 20
722.5
I'm not sure how to solve #2.
Answer:
y = 2x+10
Step-by-step explanation:
y is the cost (which we don't know)
2x is the $2 per card with x representing the number of cards (which we don't know)
And of course 10 is the cover charge.
The two long sides are 63meters and the shorter sides are 21meters.
Answer:
Step-by-step explanation:
Given the formula for calculating the distance travelled expressed as;
s=1/2at^2
Given
a = 3
t = 10
Required
lower bound of s
Substitute the given values into the equation;
s=1/2at^2
S = 1/2(3)(10)^2
S = 1/2 * 3 * 100
S = 3 * 50
S = 150
Hence the lower bound of distance S is 150
Answer:
Set up the composite result function.
g(F(x)) Evaluate g(x2−7x+14)
by substituting in the value of F into g.
g(x2−7x+14)=4(x2−7x+14)−9
Simplify each term.
g(x2−7x+14)=4x2−28x+56−9
Subtract 9 from 56.
g(x2−7x+14)=4x2−28x+47
Step-by-step explanation: