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Wewaii [24]
3 years ago
12

Ben's living room is a rectangle measuring 10 yards by 168 inches. by how many feet does the length of the room exceed the width

? please show work.please help! thank you! >-<
Mathematics
1 answer:
rjkz [21]3 years ago
5 0
Since you are going in feet first calculate10 yards into feet and then 168 inches into feet. Then subtract the two. Hope that helped :)
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I need help ASAP. Thank you :)
kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

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64° + m∠BFD = 180°

m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

m∠DFE = m∠DEF

m∠DEF = 64°

<em>sum of all the angles of a triangle = 180°</em>

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

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Collect like terms

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Solve for x

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Read more about midpoints at:

brainly.com/question/2441957

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