Answer:Step-by-step explanation:
If there is a sequence and if we are to find its 87th term we must have the general term formula for the sequence.
Normally for sequences which follow a pattern there will be a formula for nth term.
Example is arithmetic sequence nth term = a+(n-1)d where a is the I term and d the common difference.
Similarly for geometric sequence nth term
= is the nth term
Thus to find the 87th term, we must be able to find out the pattern of the sequence by which any term is related to its previous term
Either general term formula or recurring formula should be given to get the 87th term
Step-by-step explanation: is arithmetic sequence nth term = a+(n-1)d where a is the I term and d the common difference. Still stuck? Get 1-on-1 help from an expert tutor now.
(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4
y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b
so the equation is : y = -4x + 2 <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
Answer:
How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!
Step-by-step explanation:
Answer:
Inequality:
120 + 0.05x ≥ 200
Solution:
x ≥ $1,600
Her total weekly sales must be equal to or greater than $1,600
Step-by-step explanation:
Let x represent the weekly sales she must make to reach her goal.
Given;
Pay rate = $8
Weekly total work hours = 15 hours
Commission on sales = 5% = 0.05
Total weekly earnings is;
8×15 + 0.05×x
120 + 0.05x
Minimum Weekly target earnings = $200
So;
120 + 0.05x ≥ 200
Solving the inequality equation;
0.05x ≥ 200 - 120
0.05x ≥ 80
x ≥ 80/0.05
x ≥ 1600
x ≥ $1,600
Her total weekly sales must be equal to or greater than $1,600
