We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ =

π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.
R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14
a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³
b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂
</span>Vₐ = 3 × <span>

π r³
</span>Vₐ = 3 ×

3.14<span> (6.5 cm)³</span>
Vₐ = 3,449.3 cm³
c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V =

×100
V =

×100
V = 0.6666 ×100
V = 66.66%
Answer:
(a)
The values of X can be 0, 1, 2 , ..., 10 . So, X is a discrete random variable.
(b)
The distribution of X is Binomial distribution with the parameters n = 10 and p = 0.2
(c)
Probability that no one or one person will be injured = P(X = 0) + P(X = 1)
= 10C0 * 0.20 * (1 - 0.2)10-0 + 10C1 * 0.21 * (1 - 0.2)10-1
= 0.810 + 10 * 0.2 * 0.89
= 0.3758096
(d)
Average value of X = np
Average value of X = 10 * 0.2 = 2
(e)
Variance of X = np(1-p)
Variance of X = 10 * 0.2 * (1 - 0.2) = 1.6
(f)
Number of ways in which 2 people gets injured = 10C2 = 10! / ((10-2)! 2!) = (10 * 9) / (2 * 1) = 45
Assume the best player got injures, number of ways in which one people out of remaining 9 people gets injured = 9C1
= 9! / ((9-1)! 1!)
= 9
Probability that the best player got injured = Number of ways in which 1 people gets out of 9 and best person gets injured / Number of ways in which 2 people gets injured
= 9 / 45
= 0.2
Answer:
the answer to your question is 'b'
Answer:
2.8, 4.5, 5.3
numbers represent the measure of the sides of a right triangle.
2.8²+4.5²=5.3²
7.84+20.25=28.09
28.09=28.09