To find the equation of the line that passes through the given points, you first must find the slope using the slope intercept formula (y2-y1)/(x2-x1) which is used by plugging your coordinate values into the formula. This would look like this:
(5-1)/(3-1)
When simplified, you should get 4/2 or (when simplified) 2 as your slope.
Now that you have this, you can plug in one of your coordinates and your slope into y=mx+b to solve for b. Since I am using the coordinate (1,1), the equation would look like this: 1=2(1)+b
When solved for b, you should get b=-1
Finally, now that you have the b and m (slope) values, you can write your equation as y=2x-1
If you put brackets around (2+1), your method of working is:
1) 15-4*(2+1)=3
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you.
The answer is therefore: 15-4*(2+1)=3
8 seconds
The hardest part of this is setting up the equation -- the calculations are pretty easy.
You're told that the time (needed to go from 0 to 100 MPH) is inversely proportional to the horsepower: what this means is that as horsepower gets larger, time gets smaller. This makes sense since the more horsepower you have, the less time it will take you to get to 100 MPH
You can think of this as:
200 HP = 10 seconds
250 HP = x seconds
You set the equation up as:
250 HP / 200 HP = 10 sec / x sec
Now, just cross multiply and solve:
250 / 200 = 10 / x
250x = (200 x 10)
250x = 2000
x = 2000 / 250
x = 8
So, as you increase the horsepower from 200 to 250, the time decreases from 10 seconds to 8 seconds.
Hope this helps!
Good luck.
Answer:
D, B, C; see attached
Step-by-step explanation:
You want to identify the transformations from Figure A to each of the other figures.
<h3>a. Translation</h3>
A translated figure has the same orientation (left-right, up-down) as the original figure. Figure D is a translation of Figure A. The arrow of translation joins corresponding points.
<h3>b. Reflection</h3>
A figure reflected across a vertical line has left and right interchanged. Up and down remain unchanged. Figure B is a reflection of Figure A. The line of reflection is the perpendicular bisector of the segment joining corresponding points.
<h3>c. Rotation</h3>
A rotated figure keeps the same clockwise/counterclockwise orientation, but has the angle of any line changed by the same amount relative to the axes. Figure C is a 180° rotation of Figure A. The center of rotation is the midpoint of the segment joining corresponding points. Unless the figures overlap, the center of rotation is always outside the figure.
__
<em>Additional comment</em>
The center of rotation is the coincident point of the perpendicular bisectors of the segments joining corresponding points on the figure. It will be an invariant point, so will only be on or in the figure of the figures touch or overlap. In the attachment, the center of rotation is shown as a purple dot.