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3 years ago

Find the Slope and Y intercept 18x+4y=112

1 answer:

6 0

Using the formula y=mx+b, you can simplify the equation to y=-4.5x+28 which means that the slope (m) equals -4.5 and the y-intercept (b) equals 28.

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If 7x + 5 = -2, find the value of 8x

kolbaska11 [484]

Answer:

-8

Step-by-step explanation:

you add 5 to -7 to get -2

7 x -1 is -7

so x = -1

8 x -1 = -8

6 0

3 years ago

List the angles from smallest to greatest

Nonamiya [84]

I’m pretty sure it’s A.

4 0

4 years ago

Assuming that any skirt can be paired with any blouse, in how

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Don’t Ok ehhdhdh be vv

6 0

3 years ago

Given r(x) = startfraction 11 over (x minus 4) squared endfraction , which represents a domain restriction on r(x) and the corre

Dmitry_Shevchenko [17]

The domain and inverse of the function

$r(x) = \frac{11}{(x - 4)^2}$ is

Domain = $\mathbb{R} - \{4\}$ ,

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

What is a function?

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

The given function is

$r(x) = \frac{11}{(x - 4)^2}$

r(x) is not defined if x - 4 = 0

r(x) is not defined for x = 4

Domain = $\mathbb{R} - \{4\}$ ,

Where $\mathbb{R}$ is the set of all real number

Let r(x) = y

$\frac{11}{(x-4)^2} = y\\(x - 4)^2 = \frac{11}{y}\\x - 4 = \pm \sqrt{\frac{11}{y}}\\x = \pm\sqrt{\frac{11}{y}} +4$

<em /> $r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

To learn more about function, refer to the link:

brainly.com/question/22340031

#SPJ4

3 0

1 year ago

????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered

Karolina [17]

By Green's theorem, the integral of $\vec F$ along $C$ is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy$

which is 6 times the area of $D$ , the region with $C$ as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle $\theta$ and radius $r$ , the area $A$ of the sector is proportional to the circle's overall area according to

$\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3$

so that the value of the integral is

$\dfrac{6\times8\pi}3=\boxed{16\pi}$

6 0

4 years ago