The limit is some expression that is itself a function of x. Then the derivative of g(x) at x = 1 is obtained by just plugging x = 1. In other words, find g'(x) - and this can be done with or without taking a limit - then evaluate g' (1).

Alternatively, you can directly find the derivative at a point by computing the limit

$g'(1) = \displaystyle\lim_{h\to0}\frac{g(1+h)-g(1)}h$

But this is essentially the same as the first method, we're just replacing x with 1.

Yet another way is to compute the limit

$g'(1) = \displaystyle\lim_{x\to1}\frac{g(x)-g(1)}{x-1}$

but this is really the same limit with h = x - 1.

You do not compute g (1) first, because as you say, that's just a constant, so its derivative is zero. But you're not concerned with the derivative of some number, you care about the derivative of a function that depends on a variable.

8 0

3 years ago

All that make this true i need help

9966 [12]

Answer:

D and E

Step-by-step explanation:

3(23+18)=123

6(18)=108. 6(19)=114. 6(20)=120. 6(22)=132. 6(24)=144

5 0

3 years ago

-4n + 9 = -2 (2n -1) +7

valentina_108 [34]

I got u.

-4n + 9 = -4n + 9

4 0

3 years ago

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